Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 5 Lesson 16 Answer Key

Eureka Math Grade 4 Module 5 Lesson 16 Problem Set Answer Key

Question 1.
Solve.
a. 3 fifths – 1 fifth = _____2 __fifths_____

Answer:
3 fifths – 1 fifth = 2 fifths.

Explanation:
In the above-given question,
given that,
3 fifths = 3/5.
3/5 = 0.6.
1 fifth = 1/5.
1/5 = 0.2.
0.6 – 0.2 = 0.4.
2/5 = 0.4.
3 fifths – 1 fifth = 2 fifths.

b. 5 fifths – 3 fifths = _____2_fifths._________

Answer:
5 fifths – 3 fifth = 2 fifths.

Explanation:
In the above-given question,
given that,
5 fifths = 5/5.
5/5 = 1.
3 fifth = 3/5.
3/5 = 0.6.
1 – 0.6 = 0.4.
2/5 = 0.4.
3 fifths – 1 fifth = 2 fifths.

c. 3 halves – 2 halves = _____1_ halves._____

Answer:
3 halves – 2 halves = 1 halves

Explanation:
In the above-given question,
given that,
3 halves = 3/2.
3/2 = 1.5.
2 halves = 2/2.
2/2 = 1.
1.5 – 1 = 0.5.
1/2 = 0.5.
3 halves – 2 halves = 1 half.

d. 6 fourths – 3 fourths = ____3__fourths._______

Answer:
6 fourths – 3 fourths = 3 fourths.

Explanation:
In the above-given question,
given that,
6 fourths = 6/4.
6/4 = 1.5.
3 fourths = 3/4.
3/4 = 0.75.
1.5 – 0.75 = 0.75.
3/4 = 0.75.
6 fourths – 3 fourths = 3 fourths.

Question 2.
Solve.

a. \(\frac{5}{6}\) – \(\frac{3}{6}\)

Answer:
\(\frac{5}{6}\) – \(\frac{3}{6}\) = \(\frac{2}{6}\)

Explanation:
In the above-given question,
given that,
5 sixths = 5/6.
5/6 = 0.83.
3 sixths = 3/6.
3/6 = 0.5.
0.83 – 0.5 = 0.33.
2/6 = 0.33.
\(\frac{5}{6}\) – \(\frac{3}{6}\) = \(\frac{2}{6}\)

b. \(\frac{6}{8}\) – \(\frac{4}{8}\)

Answer:
\(\frac{6}{8}\) – \(\frac{4}{8}\) = \(\frac{2}{8}\)

Explanation:
In the above-given question,
given that,
6 eights = 6/8.
6/8 = 0.75.
4 eights = 4/8.
4/8 = 0.5.
0.75 – 0.5 = 0.25.
2/8 = 0.25.
\(\frac{6}{8}\) – \(\frac{4}{8}\) = \(\frac{2}{8}\)

c. \(\frac{3}{10}\) – \(\frac{3}{10}\)

Answer:
\(\frac{3}{10}\) – \(\frac{3}{10}\) = \(\frac{0}{0}\)

Explanation:
In the above-given question,
given that,
3 tens = 3/10.
3/10 = 0.3.
3 tens = 3/10.
3/10 = 0.3.
0.3 – 0.3 = 0.
0/6 = 0.
\(\frac{3}{10}\) – \(\frac{3}{10}\) = \(\frac{0}{0}\)

d. \(\frac{5}{5}\) – \(\frac{4}{5}\)

Answer:
\(\frac{5}{5}\) – \(\frac{4}{5}\) = \(\frac{1}{5}\)

Explanation:
In the above-given question,
given that,
5 fifths = 5/5.
5/5 = 1.
4 fifths = 4/5.
4/5 = 0.8.
1 – 0.8 = 0.2.
1/5 = 0.2.
\(\frac{5}{5}\) – \(\frac{4}{5}\) = \(\frac{1}{5}\)

e. \(\frac{5}{4}\) – \(\frac{4}{4}\)

Answer:
\(\frac{5}{4}\) – \(\frac{4}{4}\) = \(\frac{1}{4}\)

Explanation:
In the above-given question,
given that,
5 fours = 5/4.
5/4 = 1.25.
4 fours = 4/4.
4/4 = 1.
1.25 – 1 = 0.25.
1/4 = 0.25.
\(\frac{5}{4}\) – \(\frac{4}{4}\) = \(\frac{1}{4}\)

f. \(\frac{5}{4}\) – \(\frac{3}{4}\)

Answer:
\(\frac{5}{4}\) – \(\frac{3}{4}\) = \(\frac{2}{4}\)

Explanation:
In the above-given question,
given that,
5 fours = 5/4.
5/4 = 1.25.
3 fours = 3/4.
3/4 = 0.75.
1.25 – 0.75 = 0.5.
2/4 = 0.5.
\(\frac{5}{4}\) – \(\frac{3}{4}\) = \(\frac{2}{4}\)

Question 3.
Solve. Use a number bond to show how to convert the difference to a mixed number. Problem (a) has been completed for you.
a. Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (1)

Answer:
12/8 – 3/8 = 9/8.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
12/8 – 3/8.
9/8.
9/8 = 8/8 + 1/8.

b. \(\frac{12}{6}\) – \(\frac{5}{6}\)

Answer:
12/6 – 5/6 = 7/6.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
12/6 – 5/6.
7/6.
7/6 = 6/6 + 1/6.

c. \(\frac{9}{5}\) – \(\frac{3}{5}\)

Answer:
9/5 – 3/5 = 6/5.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
9/5 – 3/5.
6/5.
6/5 = 5/5 + 1/5.

d. \(\frac{14}{8}\) – \(\frac{3}{8}\)

Answer:
14/8 – 3/8 = 11/8.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
14/8 – 3/8.
11/8.
11/8 = 8/8 + 3/8.

e. \(\frac{8}{4}\) – \(\frac{2}{4}\)

Answer:
8/4 – 2/4 = 6/4.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
8/4 – 2/4.
6/4.
6/4 = 4/4 + 2/4.

f. \(\frac{15}{10}\) – \(\frac{3}{10}\)

Answer:
15/10 – 3/10 = 7/10.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
15/10 – 3/10.
7/10.
7/10 = 10/10 + 1/6.

Question 4.
Solve. Write the sum in unit form.

a. 2 fourths + 1 fourth = _3 fourths._

Answer:
2 fourths + 1 fourth = 3 fourths.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
2 fourths = 1/4 + 1/4.
2 fourths + 1 fourth = 3 fourths.
1/4 + 1/4 + 1/4 = 3/4.

b. 4 fifths + 3 fifths = ____7__fifths.___

Answer:
4 fifths + 3 fifths = 7 fifths.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
4 fifths = 1/5 + 1/5 + 1/5 + 1/5.
3 fifths = 1/5 + 1/5 + 1/5.
4 fifths + 3 fifths = 7 fifths.
1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 7/5.

Question 5.
Solve.
a. \(\frac{2}{8}\) + \(\frac{5}{8}\)

Answer:
\(\frac{2}{8}\) + \(\frac{5}{8}\) = \(\frac{7}{8}\)

Explanation:
In the above-given question,
given that,
2 eights = 2/8.
2/8 = 0.25.
5 eights = 5/8.
5/8 = 0.625.
0.25 + 0.625 = 0.875.
7/8 = 0.875.
\(\frac{2}{8}\) + \(\frac{5}{8}\) = \(\frac{7}{8}\)

b. \(\frac{4}{12}\) + \(\frac{5}{12}\)

Answer:
\(\frac{4}{12}\) + \(\frac{5}{12}\) = \(\frac{9}{12}\)

Explanation:
In the above-given question,
given that,
4 twelfths = 4/12.
4/12 = 0.33.
5 twelfths = 5/12.
5/12 = 0.41.
0.33 + 0.41 = 0.74.
9/12 = 0.74.
\(\frac{4}{12}\) + \(\frac{5}{12}\) = \(\frac{9}{12}\)

Question 6.
Solve. Use a number bond to decompose the sum. Record your final answer as a mixed number.
Problem (a) has been completed for you.

a. Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (2)

Answer:
3/5 + 4/5 = 7/5.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/5 + 4/5.
7/5.
7/5 = 5/5 + 2/5.

b. \(\frac{4}{4}\) + \(\frac{3}{4}\)

Answer:
4/4 + 3/4 = 7/4.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
4/4 + 3/4.
7/4.
7/4 = 4/4 + 3/4.

c. \(\frac{6}{9}\) + \(\frac{6}{9}\)

Answer:
6/9 + 6/9 = 12/9.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
6/9 + 6/9.
12/9.
12/9 = 9/9 + 3/9.

d. \(\frac{7}{10}\) + \(\frac{6}{10}\)

Answer:
7/10 + 6/10 = 13/10.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
7/10 + 6/10.
13/10.
13/10 = 10/10 + 3/10.

e. \(\frac{5}{6}\) + \(\frac{7}{6}\)

Answer:
5/6 + 7/6 = 12/6.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/6 + 7/6.
12/6.
12/6 = 6/6 + 7/6.

f. \(\frac{9}{8}\) + \(\frac{5}{8}\)

Answer:
9/8 + 5/8 = 14/8.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
9/8 + 5/8.
14/8.
14/8 = 8/8 + 6/8.

Question 7.
Solve. Use a number line to model your answer.
a. \(\frac{7}{4}\) – \(\frac{5}{4}\)

Answer:
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{2}{4}\)

Explanation:
In the above-given question,
given that,
7 fours = 7/4.
7/4 = 1.75.
5 fours = 5/4.
5/4 = 1.25.
1.75 – 1.25 = 0.5.
2/4 = 0.5.
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{2}{4}\)

b. \(\frac{5}{4}\) + \(\frac{2}{4}\)

Answer:
5/4 + 2/4 = 7/4.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/4 + 2/4.
7/4.
7/4 = 4/4 + 3/4.

Eureka Math Grade 4 Module 5 Lesson 16 Exit Ticket Answer Key

Question 1.
Solve. Use a number bond to decompose the difference. Record your final answer as a mixed number.
\(\frac{16}{9}\) – \(\frac{5}{9}\)

Answer:
16/9 – 5/9 = 11/9.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
16/9 – 5/9.
11/9.
11/9 = 9/9 + 2/9.

Question 2.
Solve. Use a number bond to decompose the sum. Record your final answer as a mixed number.
\(\frac{5}{12}\) + \(\frac{10}{12}\)

Answer:
5/12 + 10/12 = 15/12.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/12 + 10/12.
15/12.
15/12 = 12/12 + 3/12.

Eureka Math Grade 4 Module 5 Lesson 16 Homework Answer Key

Question 1.
Solve.
a. 3 sixths – 2 sixths = __1__sixths___________

Answer:
3 sixths – 2 sixths = 1 sixths.

Explanation:
In the above-given question,
given that,
3 sixths = 3/6.
3/6 = 0.5.
2 sixths = 2/6.
2/6 = 0.33.
0.5 – 0.3 = 0.1.
1/6 = 0.1.

b. 5 tenths – 3 tenths = ___2 tenths._____

Answer:
5 tenths – 3 tenths = 2 tenths.

Explanation:
In the above-given question,
given that,
5 tenths = 5/10.
5/10 = 0.5.
3 tenths = 3/10.
3/10 = 0.3.
0.5 – 0.3 = 0.2.
2/10 = 0.2.

c. 3 fourths – 2 fourths = ____1__fourth._________

Answer:
3 fourths – 2 fourths = 1 fourth.

Explanation:
In the above-given question,
given that,
3 fourths = 3/4.
3/4 = 0.75.
2 fourths = 2/4.
2/4 = 0.5.
0.75 – 0.5 = 0.25.
1/4 = 0.25.

d. 5 thirds – 2 thirds = ___3__thirds._____

Answer:
5 thirds – 2 thirds = 3 thirds.

Explanation:
In the above-given question,
given that,
5 thirds = 5/3.
3/5 = 1.6.
2 thirds = 2/3.
2/3 = 0.6.
1.6 – 0.6 = 1.
3/3 = 1.

Question 2.
Solve.

a. \(\frac{3}{5}\) – \(\frac{2}{5}\)

Answer:
\(\frac{3}{5}\) – \(\frac{2}{5}\) = \(\frac{1}{5}\)

Explanation:
In the above-given question,
given that,
3 fives = 3/5.
3/5 = 0.6.
2 fives = 2/5.
2/5 = 0.4.
0.6 – 0.4 = 0.2.
1/5 = 0.2.
\(\frac{3}{5}\) – \(\frac{2}{5}\) = \(\frac{1}{5}\)

b. \(\frac{7}{9}\) – \(\frac{3}{9}\)

Answer:
\(\frac{7}{9}\) – \(\frac{3}{9}\) = \(\frac{4}{9}\)

Explanation:
In the above-given question,
given that,
7 nines = 7/9.
7/9 = 0.7.
3 nines = 3/9.
3/9 = 0.3.
0.7 – 0.3 = 0.4.
4/9 = 0.4.
\(\frac{7}{9}\) – \(\frac{3}{9}\) = \(\frac{4}{9}\)

c. \(\frac{7}{12}\) – \(\frac{3}{12}\)

Answer:
\(\frac{7}{12}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\)

Explanation:
In the above-given question,
given that,
7 twelfths = 7/12.
7/12 = 0.58.
3 twelfths = 3/12.
3/12 = 0.25.
0.58 – 0.25 = 0.33.
4/12 = 0.33.
\(\frac{7}{12}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\)

d. \(\frac{6}{6}\) – \(\frac{4}{6}\)

Answer:
\(\frac{6}{6}\) – \(\frac{4}{6}\) = \(\frac{2}{6}\)

Explanation:
In the above-given question,
given that,
6 sixs = 6/6.
6/6 = 1.
4 sixs = 4/6.
4/6 = 0.6.
1 – 0.6 = 0.4.
2/6 = 0.4.
\(\frac{6}{6}\) – \(\frac{4}{6}\) = \(\frac{2}{6}\)

e. \(\frac{5}{3}\) – \(\frac{2}{3}\)

Answer:
\(\frac{5}{3}\) – \(\frac{2}{3}\) = \(\frac{3}{3}\)

Explanation:
In the above-given question,
given that,
5 threes = 5/3.
5/3 = 1.6.
2 threes = 2/3.
2/3 = 0.6.
1.25 – 1 = 0.25.
3/3 = 1.
\(\frac{5}{3}\) – \(\frac{2}{3}\) = \(\frac{3}{3}\)

f. \(\frac{7}{4}\) – \(\frac{5}{4}\)

Answer:
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{3}{4}\)

Explanation:
In the above-given question,
given that,
7 fours = 7/4.
7/4 = 1.75.
5 fours = 4/4.
5/4 = 1.25.
1.75 – 1.25 = 0.75.
3/4 = 0.75.
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{3}{4}\)

Question 3.
Solve. Use a number bond to decompose the difference. Record your final answer as a mixed number. Problem (a) has been completed for you.
Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (3)

Answer:
12/6 – 3/6 = 9/6.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
12/6 – 3/4.
9/6.
9/6 = 6/6 + 3/6.

b. \(\frac{17}{8}\) – \(\frac{6}{8}\)

Answer:
17/8 – 6/8 = 11/8.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
17/8 – 6/8.
11/8.
11/8 = 8/8 + 2/8.

c. \(\frac{9}{5}\) – \(\frac{3}{5}\)

Answer:
9/5 – 3/5 = 6/5.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
9/5 – 3/5.
6/5.
6/5 = 5/5 + 1/6.

d. \(\frac{11}{4}\) – \(\frac{6}{4}\)

Answer:
11/4 – 6/4 = 5/4.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
11/4 – 6/4.
5/4.
5/4 = 4/4 + 1/4.

e. \(\frac{10}{7}\) – \(\frac{2}{7}\)

Answer:
10/7 – 2/7 = 8/7.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
10/7 – 2/7.
8/7.
8/7 = 7/7 + 1/7.

f. \(\frac{21}{10}\) – \(\frac{9}{10}\)

Answer:
21/10 – 9/10 = 11/10.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
21/10 – 9/10.
11/10.
11/10 = 10/10 + 1/10.

Question 4.
Solve. Write the sum in unit form.
a. 4 fifths + 2 fifths = ____6__fifths.____

Answer:
4 fifths + 2 fifths = 6 fifths.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
4 fifths = 1/5 + 1/5 + 1/5 + 1/5.
2 fifths = 1/5 + 1/5.
4 fifths + 2 fifth = 6 fifths.
1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 6/5.

b. 5 eighths + 2 eighths = __7___eights.______

Answer:
5 eights + 2 eighths = 7 eights.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
5 eights = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
2 eights = 1/8 + 1/8.
5 eights + 2 eights = 7 eights.
1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 7/8.

Question 5.
Solve.
a. \(\frac{3}{11}\) + \(\frac{6}{11}\)

Answer:
3/11 + 6/11 = 9/11.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/11 + 6/11.
9/11.
9/11 = 3/11 + 9/11.

b. \(\frac{3}{10}\) + \(\frac{6}{10}\)

Answer:
3/10 + 6/10 = 9/10.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/10 + 6/10.
9/10.
9/10 = 3/10 + 6/10.

Question 6.
Solve. Use a number bond to decompose the sum. Record your final answer as a mixed number.
a. \(\frac{3}{4}\) + \(\frac{3}{4}\)

Answer:
3/4 + 3/4 = 6/4.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/4 + 3/4.
6/4.
6/4 = 4/4 + 5/4.

b. \(\frac{8}{12}\) + \(\frac{6}{12}\)

Answer:
8/12 + 6/12 = 14/12.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
8/12 + 6/12.
14/12.
14/12 = 12/12 + 2/12.

c. \(\frac{5}{8}\) + \(\frac{7}{8}\)

Answer:
5/8 + 7/8 = 12/8.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/8 + 7/8.
12/8.
12/8 = 8/8 + 4/8.

d. \(\frac{8}{10}\) + \(\frac{5}{10}\)

Answer:
8/10 + 5/10 = 13/10.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
8/10 + 5/10.
13/10.
13/10 = 10/10 + 3/10.

e. \(\frac{3}{5}\) + \(\frac{6}{5}\)

Answer:
3/5 + 6/5 = 9/5.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/5 + 6/5.
9/5.
9/5 = 5/5 + 4/5.

Question 7.
Solve. Use a number line to model your answer.

a. \(\frac{11}{9}\) – \(\frac{5}{9}\)

Answer:
\(\frac{11}{9}\) – \(\frac{5}{9}\) = \(\frac{6}{9}\)

Explanation:
In the above-given question,
given that,
11 nines = 11/9.
11/9 = 0.58.
5 nines = 5/9.
5/9 = 0.25.
0.58 – 0.25 = 0.33.
6/9 = 0.33.
\(\frac{11}{9}\) – \(\frac{5}{9}\) = \(\frac{6}{1}\)

b. \(\frac{13}{12}\) + \(\frac{4}{12}\)

Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (2024)

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Eureka Math is scripted for the teacher and anticipates student responses, which is very useful for studying in advance. This makes each module easy to follow and easy to understand what is expected.

How many states use Eureka math? ›

We wrote EngageNY Math, and over time we developed that program into Eureka Math. The original OER curriculum is available on the EngageNY and Great Minds sites for free, and it has been downloaded over 13 million times by users in all 50 states, making Eureka Math the most widely used K–5 math program in the country.

What are the 4 parts of the TEKS? ›

Explore how the TEKS are organized by Introduction, Knowledge and Skill Statement, Strand, and Student Expectations across a grade level or course. Recognize and differentiate between cognitive and content expectations noted in the TEKS.

Why are schools using Eureka Math? ›

Eureka Math, a Common Core-aligned curriculum published by the non-profit Great Minds Inc., equates mathematical concepts to stories, with the aim of developing conceptual understanding.

Who invented Eureka Math? ›

Eureka (Ancient Greek: εὕρηκα, romanized: héurēka) is an interjection used to celebrate a discovery or invention. It is a transliteration of an exclamation attributed to Ancient Greek mathematician and inventor Archimedes.

Who is the father of math Eureka? ›

Here's a closer look into this sudden discovery (the “Eureka!” moment): The famous Greek mathematician, physicist, and astronomer, Archimedes was born in 287 BC in Syracuse, a Greek colony in Sicily (an island now part of Italy).

What are the parts of the Eureka math lesson? ›

The Anatomy of a Eureka Math Lesson
  • Fluency: these activities are focused on one of the following: preparation, maintenance, or anticipation of knowledge and skills.
  • Application Problem: requires students to utilize the concepts they've just learned.
  • Concept Development: the part of the lesson focused on new learning.
Jan 10, 2017

How is Eureka Math organized? ›

The content in Eureka Math is organized around a story that merges its content. This story builds learners' understanding of concepts and improves their ability to manipulate units. Through Eureka Math, students learn commonalities between units and the unique features of the units.

What are the goals of Eureka Math? ›

Eureka Math is designed to support students in gaining a solid understanding of concepts, a high degree of procedural skill and fluency, and the ability to apply math to solve problems in and outside the classroom. There is also an intentional coherence linking topics and thinking across grades.

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What is 8th grade advanced math? ›

Eighth graders who score proficient or advanced are considered to have mastered concepts such as number sense and operations; expressions, equations, and inequalities; functions; geometry and measurement; and data, analysis, and statistics.

What grade level does prodigy math go up to? ›

With 1,500+ curriculum-aligned math skills for 1st to 8th grade, Prodigy Math is so much more than a game. Prodigy Math is an engaging game-based learning platform that's dedicated to improving students' confidence and achievements in math.

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